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Dolphins claim TE A.J. Derby, waive Rashawn Scott; Promote De’Veon Smith

NFL: Arizona Cardinals at Denver Broncos Isaiah J. Downing-USA TODAY Sports

The Miami Dolphins announced on Wednesday they had been awarded tight end A.J. Derby off waivers from the Denver Broncos. Derby played in nine games for the Broncos this season, catching 19 passes for 224 yards and two touchdowns. He played part of the 2016 season with the New England Patriots before being traded to Denver.

He was a 2015 sixth-round pick of the Patriots.

Derby was designated as waived/injured by the Broncos when they released him due to a shoulder injury. He had been placed on injured reserve prior to the move to release him.

There is not an indication of whether or not Derby will be available to play for the Dolphins this season.

To make roster space for Derby, the Dolphins waived wide receiver Rashawn Scott. Scott made one appearance for Miami this season and has been inactive for three games after starting the year on the Physically Unable to Perform list. He was signed by Miami as an undrafted free agent before the 2016 season, appearing in two games as a rookie, as well as the team’s playoff game last year.

Earlier in the day, the team also announced they had promoted running back De’Veon Smith from the practice squad to the 53-man roster. Smith has spent 10 of the team’s first 11 games on the practice squad, but was on the 53-man roster for one contest, though he was inactive. He was signed as an undrafted free agent this offseason. He fills the roster spot vacated by defensive end William Hayes, who was placed on injured reserve on Tuesday.