Ryan Tannehill named AFC Offensive Player of the Week

The NFL selected Cameron Wake as the AFC Defensive Player of the Week in Week 6 following his four sack, two forced fumble performance against the Tennessee Titans. It did not take long for the Miami Dolphins to pick up another AFC Player of the Week award as the league announced on Wednesday that quarterback Ryan Tannehill was named the AFC Offensive Player of the Week. It also marked the third time a Dolphins player has received the Player of the Week recognition this year, with Wake and Tannehill joined by wide receiver Jarvis Landry, who was selected the Week 1 AFC Special Teams Player of the Week - marking the first time since 1999 the Dolphins have had players honored in all three aspects of the game in a single season.

Tannehill was surgical in his precision in Week 7, carving up the Houston Texans' defense. He finished the game 18-for-19 for 282 yards with four touchdowns. He ended the game with a perfect 158.3 passer rating. All four touchdowns came in the first half for Miami, with three of them coming from at least 50 yards away from the endzone, making him the first quarterback since Randall Cunningham in 1998 with three 50-plus yard touchdown in first half of a game.

Tannehill completed his first 18 passes of the game, which, along with the 7 completions he had to end the team's Week 6 game, set a new NFL record of 25 straight completions.

This is the first time Tannehill has earned AFC Offensive Player of the Week honors in his career. He is the seventh Dolphins quarterback to be recognized, joining Dan Marino (20 times overall, 18 regular season), Scott Mitchell (twice), Jay Fiedler (once), Cleo Lemon (once), Chad Pennington (once) and Matt Moore (once). Tannehill's recognition is the 42nd time a Dolphins player has received the AFC Offensive Player of the Week honor, with running back Reggie Bush last winning it in Week 11 of the 2012 season.